25p^2+10p-17=0

Solution for 25p^2+10p-17=0 equation:

25p^2+10p-17=0

a = 25; b = 10; c = -17;
Δ = b2-4ac
Δ = 102-4·25·(-17)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30\sqrt{2}}{2*25}=\frac{-10-30\sqrt{2}}{50}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30\sqrt{2}}{2*25}=\frac{-10+30\sqrt{2}}{50}
$